How to measure the strength of a punching bag?

2 min

How to measure the strength of a punching bag?

The strength of an object is a product of the acceleration and mass of that object. The English physicist Isaac Newton introduced this fundamental identity of classical mechanics with the second law of motion, F = ma. F represents force, m represents mass, and variable a represents acceleration. The fist of a boxer or a boxer’s glove when it reaches a punching bag will have a strength depending on how fast the fist or glove is accelerating and the mass of the fist or glove and arm. The unit of force is typically the Newton (N), which is one meter kilogram per square second.

Weigh the boxer or fighter with the scale. For example, the boxer weighs 147.7 pounds.

Multiply the wrestler’s weight by 0.0345 with a calculator to determine the mass of the boxer’s arm. For example, 0.0345 x 67 = 2.311. The estimated mass of this boxer’s arm, according to Pennsylvania State University’s VM Zatsiorsk, is 2.3 kilograms.

Place the boxer in front of a punching bag. Place two individuals to the right and left of the boxer. Individuals must be facing each other with a line of sight perpendicular to the direction in which the fighter punches. Equip one individual with a digital chronometer and the other with a speedometer.

Tell the person holding the speedometer to do so immediately to the left of the surface of the boxing bag in front of the boxer. Tell the person holding the stopwatch to start it when the boxer starts his movement and stop him when the boxer’s fist hits the punching bag.

Tell the boxer to hit the bag, allowing the two people to take their measurements. For example, the person holding the stopwatch measures a time of 0.1 seconds; The person holding the speedometer measures a speed of 19.0 mph.

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Multiply the hit speed by 1.61 to convert the speed to kilometers per hour using a calculator. For example, 19 x 1.61 = 30.59. Multiply the result by 0.277 to convert the hit speed in meters per second. For example, 30.59 x 0.2778 = 8.49. The boxer’s stroke speed was approximately 8.49 meters per second (m / s).

Divide the result by the measured time of the stroke. For example, the time measured was 0.1 seconds: 8.49 / 0.1 = 84.9. The fist acceleration and arm of the boxer was approximately 84.9 meters per second squared (m / s ^ 2).

Multiply the result by the calculated mass of the boxer’s arm in kilograms. For example, 84.9 x 2.3 = 195.27. The strength of this boxer’s blow when it reaches the punching bag is about 195 meters kilogram per second squared, or 195 Newtons (N).

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